Chemistry, asked by 1anandshukla98, 1 year ago

electron fall from n=3 to n=2 ,then emitted energy is :

Answers

Answered by Noreen1256
8

Energy of n= 2 is -328.32 kj / mole
Energy of n= 3 is - 145.92kj / mole

So
E3 - E2 = - 145.92 - (-328.32)
= 182.4 kj / mole. ..


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Noreen1256: To determine in kcal / mole decide value by 4.18
Noreen1256: Ans will be 43.6 which is approximately correct....
1anandshukla98: madam -313.6/n2 in (k cal/mol) and solve them answer is 44.3
Noreen1256: My ans was in kj / mole and this is also correct ....
1anandshukla98: kk
Noreen1256: Is tarha tb krtai h jb 1 shell given ho jb 2 given h to 2no ki values isi farmulai se nikal kr minus krai gai ... jis tarha mene kiya ... and bus fark ye h merI values kj / mole me h.....
Noreen1256: Mark as brainlist plz PlzZ ...
Noreen1256: If you are satisfied
1anandshukla98: i konow jb 2 shell maine ab n2 me (n1)2-(n2)2 kr ke bhi solve kr sakte hh
Noreen1256: Ji thk h is tarha kr sktai h...
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