Question

electron moving with a velocity of
5
×
10
3
m
/
s
enters into a uniform electric field and acquires a uniform acceleration of
10
3
m
/
s
2
in the direction of initial velocity.
i. Find out the time in which electron velocity will be doubled.?
ii. How much distance electron would cover in this time.?​

Answer 1

Answer:

Initial velocity of the electron is u =5×10

4

m/s

Acceleration of the electron is a=10

4

m/s

2

From first equation of motion,

v=u+at

2u=u+at

t=u/a=(5×10

4

)/(10

4

)=5s