Chemistry, asked by anushreewani498, 7 months ago

electronic configuration of four element A,B,C,D are as follow which will be most metallic
1 A=2,4,8
2 B=2,8,8
3 C=2,8,1
4D=2,8,8,7​

Answers

Answered by singhamanpratap0249
7

Answer:

C > A > B > D

........

.. . ...

Explanation:

Metallic character refers to the level of reactivity of a metal. Metals tend to lose electrons in chemical reactions, as indicated by their low ionization energies. Within a compound, metal atoms have relatively low attraction for electrons, as indicated by their low electronegativities.

Answered by atharvakapgate0464
0

Answer: here is your answer

Explanation:(A) 1s

2

2s

2

2p

6

: Total electrons =2+2+6=10 Its a completely filled electronic cofiguration i.e. group 18 element Neon. This element has positive electron gain enthalpy.

(B) 1s

2

2s

2

2p

4

: The electronic configuration is for group 16 element i.e. oxygen. This elementhas high negative electron gain enthalpy.

(C) 1s

2

2s

2

2p

6

3s

1

: The electronic configuration is for group 1 element i.e. Sodium. This element has low negative electron gain enthalpy.

(D) 1s

2

2s

2

2p

5

: The electronic configuration is for group 17 element i.e. Fluorine. This element has highest negative electron gain enthalpy among the given configurations.

Thus increasing order of elelctron gain enthalpies for the given configurations is:

A<C<B<D

I hope this answer will be very clear to you and I request you to mark as brinlist

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