Question

Electronic configuration of sodium is 1s² 2s² 2p⁶ 3s¹ Then write the
4 quantum numbers of the first electron in the 'K' shell.​

Answer 1

Answer:

the four quantum numbers are

Principle quantum number (n) =1

azimuthal quantum number (l) =0

magnetic quantum number(ml)=0

spin quantum number (ms)=+1/2

Answer 2

Answer:

The 4 quantum numbers of the first electron in the 'K' shell are n = 1, s = 0, m = 0, and s = +1/2.

Explanation:

Given,

The electronic configuration of the sodium atom (Na) with atomic number Z = 11 is 1s² 2s² 2p⁶ 3s¹.

To find,

The 4 quantum numbers of the first electron in the 'K' shell.

Calculation,

For the 'K' shell of the first electron:

The Principle quantum number (n) = 1 (As K is the first shell in the series of shells K, L, M, N....).

The Azimuthal quantum number (l) = 0 (As l = (n - 1), so l = (1 - 1) = 0).

The magnetic quantum number (m) = 0 (As m has the range from -l to +l, l = azimuthal quantum number).

The spin quantum number (s) = +1/2 (As s can be +1/2 or -1/2).

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