Element A forms tripositive ion and element B forms dinegative ion the chemical formula of the compound formed with Aand B will be
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Answer:
I Hope it will work.
Explanation:
Atom 'A' at FCC lattice points means number of atom A in unit cell is:
8
1
×8+
2
1
×6=4.
If in a close-packed structure (ccp or fcc) there are 'n' atoms or ions then the number of tetrahedral voids will be 2n. Thus the number of atom B is =2×4=8
Thus the compound is A
4
B
8
or AB
2
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