Element A has atomic number 16&B has atomic number 13. Using ionic half equation show how A&B will form ions
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A^-2 and B^+3.
that's how the ions will be formed.
that's how the ions will be formed.
Soumikdash135:
I can't understand
electronic configuration of A is 2, 8, 6. so it will gain 2 electrons to complete its octet and is the case with B
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A has atomic no 16 therefore it wants to take up 2 electrons to attain the nearest noble gas configuration of argon which has an atomic no of 18. Therefore,
A + 2e^- -> A^2-
B has atomic no 13 therefore it wants to give away 3 electrons to attain the nearest noble gas configuration of neon which has atomic no 10. Therefore,
B -> B^3+ + 3e^-
A + 2e^- -> A^2-
B has atomic no 13 therefore it wants to give away 3 electrons to attain the nearest noble gas configuration of neon which has atomic no 10. Therefore,
B -> B^3+ + 3e^-
I can't understand
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