Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):
Find the probability that any of these bags chosen at random contains more than 5 kg of flour.
Answers
Total number of wheat bags==11
So,that the number bags having more than 5 kilograms =7
Probability of a bag contain more than 5 kilograms ==7/11
P is 7/11
____________________❤
Concept: Probability is the study of the chances of events happening.
Required probability = Number of trials in which the event happens/Total number of trials
Given: Eleven bags of wheat flour, each marked 5 kg, actually contained the following weights of flour (in kg):
4.97 5.05 5.08 5.03 5.00 5.06 5.08 4.98 5.04 5.07 5.00
Total numbers of wheat flour bags = 11
The weight of flour more than 5 kg are 5.05, 5.08, 5.03, 5.06, 5.08, 5.04, 5.07
Numbers of bags containing more than 5 kg of flour = 7
Required probability, P(more than 5 kg of flour) = 7/11
P(more than 5 kg of flour) = 7/11
Hence, the probability that any of these bags chosen at random contains more than 5 kg of flour is 7/11.
HOPE THIS ANSWER WILL HELP YOU…..
Similar questions :
A coin is tossed 1000 times with the following frequencies: Head: 455, Tail: 545 Compute the probability for each event.
https://brainly.in/question/15913878
The blood groups of 30 students of class iX are recorded as follows :
A, B, O, O, AB, O, A, O, B, A, O, B, A, O, O
A, AB, O, A, A, O, O, AB, B, A, O, B, A , B, O
A student is selected at random from the class from blood donation. Find the probability that the blood group of the student chosen is :
(i) A
(ii) B
(iii) AB
(iv) O
https://brainly.in/question/15913882