Math, asked by kesavankishore, 4 months ago

elimination
3X-5 y=20 method
6x-10y = 40

Answers

Answered by RounaqBag

0

Step-by-step explanation:

Answer is 0

please mark me brainleast

Answered by vipashyana1

0

Answer:

3x-5y=20--eq1

6x-10y=40--eq2

Multiply eq1 by 2

2×(3x-5y=20)

6x²-10y=40--eq3

when we add eq1 and eq2, we get zero.

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