Question

Ella has 0.5 lbs of sugar. How much water should she add to 75% syrup to make a concentration?

Pls HELP ME!!!

Answer 1

Answer:

Step-by-step explanation:

Suppose amount of water in lbs is A

mass of solution = mass of water + mass of sugar

mass of solution = (A + 0.5) lbs

concentration = (mass of sugar/mass of solution) × 100

75 = 0.5/(A + 0.5) × 100

75/100 = 0.5/(A + 0.5)

0.75 = 0.5/(A + 0.5)

0.75*A + 0.75*0.5 = 0.5;

0.75*A = 0.5-0.375 = 0.125;

A = 0.16 lbs

hence, amount of water is

0.5 lbs of sugar = 0.22 kg;

75% syrup to make a concentration means 0.75A is water;

0.25A = 0.22;

A = 0.88;

75% syrup = (75*0.88)/100 = 0.66 water be added:

Answer 2

Let amount of water in lbs is x

so, mass of solution = mass of water + mass of sugar

= (x + 0.5) lbs

concentration of syrup = mass of sugar/mass of solution × 100

75 = 0.5/(x + 0.5) × 100

or, 75/100 = 0.5/(x + 0.5)

or, 3/4 = 0.5/(x + 0.5)

or, 3x + 3 × 0.5 = 4 × 0.5

or, 3x + 1.5 = 2

or, 3x = 0.5

or, x = 0.167 lbs

hence, amount of water is 0.167 lbs