Elliott is counting the change from a class fundraiser. He has half as many quarters as nickels, and he has 7 fewer dimes than nickels. The total value of coins is $5.90. He wrote the equation 0.10 (7 minus x) + 0.5 (x) + 0.25 (one-half x) = 5.90. Which statements identify Elliott’s errors? Check all that apply. He should have written the expression for the number of dimes as x – 7. He should have written the coin values as 5, 10, and 25 and not as 0.5, 0.10, and 0.25. He should have written the coin value for the nickel as 0.05. He should have translated the scenario as value of all dimes = value of all nickels and value of all quarters = value of all nickels. He should have written the expression for number of nickels as 2x.
Answers
Given : Elliott is counting the change from a class fundraiser. He has half as many quarters as nickels, and he has 7 fewer dimes than nickels. The total value of coins is $5.90. He wrote the equation 0.10 (7 minus x) + 0.5 (x) + 0.25 (one-half x) = 5.90
To Find : Which statements identify Elliott’s errors?
Solution:
half as many quarters as nickels, and he has 7 fewer dimes than nickels.
niickles = x
Quarters = x/2
Dimes = x - 7
Value of nickles = 0.5
Value of Quarter = 0.25
Value of Dimes = 0.1
=> 0.1 (x - 7) + 0.5x + 0.25(x/2) = 5.9
He wrote the equation 0.10 (7 - x) + 0.5 (x) + 0.25 (x/2) = 5.90.
He should have written the expression for the number of dimes as x – 7
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