Question

❤ Ello! Folks! ❤

I'm here with A new question ✔

➡Find the area of A rhombus ABCD whose vertices are A(3,0) , B(4,5) , C(-1,4) and D(-2,-1).

✨ I need proper solution ✨

↪No useless answers.....❎​

Answer 1

Step-by-step explanation:

$Always \: remember..... \\ for \: any \: quadrilateral \: this \: formula \: works \\here \\ (x1,y1) = (3,0) \\ (x2,y2) = (4,5) \\ (x3,y3) = ( - 1,4) \\ (x4,y4) = ( - 2,- 1) \\ \\ AREA = \\ \frac{1}{2} |(x1y2 - y1x2) + (x2y3 - y2x3) \\ + (x3y4 - y3x4) + (x4y1 - y4x1)| \\ \frac{1}{2} |(15 -0) + (16 + 5) + (1 + 8) + (0 + 3) | \\ \frac{1}{2} |15 + 21 + 9 + 3| \\ \frac{1}{2} |48| \\ 24 \: sq \: cm$

Answer 2

Answer:

Hey radhika! Here is a simpler solution.

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