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If Zeroes. of the polynomial x²+px+q are 3 and 2 .find the value of p&q and write the polynomial ...
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Solution
If p = 2,
=> p ( 2 ) = (2)² - 2p = q
=> p ( 2 ) = 4 - 2p = q ... ( 1)
If p = 3
=> p ( 3 ) = (3)² - 3p = q
=> p ( 3 ) = 9 - 3p = q. ...... (2)
From the equation 1 and 2, we get
4 - 2p = 9 - 3p ------(1)
4 - 9 = -3p + 2p ----(2)
★ "4" and "-3p" are cancelled
=> ( -5 ) = -p
[ .°. p = 5 ]
Now, for "q",
=> q = 4 - 2p
=> q = 4 - 2*5
[ .°. q = ( -6 ) ]
Now, putting the value of p and q in this written equation.
=> p(x) = x² + px + q
Therefore, p(x) = x² + 5x - 6
Hence, the resultant polynomial is x² + 5x - 6.
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