Question

Ello❤
please solve fast.... ​

Answer 1

plse mark as brainlist ...

Answer 2

Answer:

T = 2 π / √ 3

v_max =  2 √ 3 m / sec

a_max = - 6 m / sec²

Explanation:

Given :

Amplitude A = 2 cm

Displacement of particle from mean position x = 1 cm

It is said acceleration is equal to velocity of particle.

ω ( √ A² - x² ) =  ω² x

ω x = ( √ A² - x² )

Putting value here :

ω  = ( √ 4 - 1 )

ω = √ 3

We know :

ω = 2 π / T

T = 2 π / √ 3 .

Now for :

v_max = A ω

v_max = 2 × √ 3

v_max =  2 √ 3 m / sec

For a_max = - A ω²

a_max = - 2 ( √ 3 )²

a_max = - 6 m / sec²

Hence we get answer.

$\:$