Physics, asked by tajinderkaur8780, 9 months ago

Elocity of a particle increases from 10 m/s to 15 m/s. what will be its acceleration after a time interval of 1 minute.immersive reader
(2 points)
3.33 metre per second sq
33.3 metre per second sq
0.03 metre per second sq
3 metre per second sq

Answers

Answered by BrainlyConqueror0901
52

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Acceleration=0.0834\:m/s^{2}}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given :}} \\  \tt:   \implies Initial\:velocity(u) =10  \: m/{s}\\  \\  \tt:  \implies Final \: velocity(v) = 15 \: m/s\\\\ \tt:\implies Time(t)=60\:sec \\  \\ \red{\underline \bold{To \: Find :}}  \\ \tt:  \implies Acceleration(a) = ?

• According to given question :

 \bold{As \: we \: know \: that} \\  \tt:  \implies v = u + at \\  \\ \tt:  \implies 15 =  10 + a \times 60 \\  \\ \tt:  \implies 15 - 10 = a \times 60 \\  \\ \tt:  \implies 5 = a \times 60 \\  \\ \tt:  \implies a =  \frac{5}{60}  \\  \\  \green{\tt:  \implies a = 0.0834 \:  {m/s}^{2} } \\  \\  \blue{ \bold{some \: related \: formula}} \\  \orange {\tt \circ \:  {v}^{2}  =  {u}^{2}  + 2as} \\  \\ \orange {\tt \circ \: s=  u t +  \frac{1}{2} {at}^{2}  }

Answered by Saby123
46

.2pts..

 \tt{\huge{\purple{ .............. }}}

CORRECT QUESTION -

Velocity of a particle increases from 10 m/s to 15 m/s in 5 Seconds.

What will be its acceleration after a time interval of 1 minuite ?

1. 3.33 metre per second sq.

2. 33.3 metre per second sq.

3. 0.03 metre per second sq.

4. 3 metre per second sq.

SOLUTION -

In the above Question, we have the following information....

Velocity of a particle increases from 10 m/s to 15 m/s in 5 Seconds.

Here, the initial velocity of the Particle is 10 m / s

We know that :

1 minuite = 60 seconds.

So,

According to Newton ' s first law of motion -

A = { V - U } / t

Where :

V is the final Velocity.

U is the innitial velocity.

t is the time period.

Here,

Acceleration = { 15 - 10 } / 60 ={ 1/ 12} m / s ^ 2. = 0.0834 m / s ^ 2.

So the acceleration of the body after 1 minuite becomes 0.00834 m / s ^ 2.

None of the given options are correct.

ANSWER :

THE acceleration of the body after 1 minuite becomes 0.00834 m / s ^ 2.

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