Emergency. What fraction of free electrons in 20 gram of copper is passing through a cross section of the copper wire in 2 seconds. Given : Mass of copper is 63.5 gram. Avogadro number 6.022*10 23.
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w = E/ 96500 x I x t
hence 20 = 63.5/ 2 / 96500 x Ixt
Ix t = 20 x 96500 / 31.75 = 60787 C of electricity
96500 C passes 1 mole of electrons
hence 60787 will pass 1/96500 x 60787 moles of electrons = 0.6299 moles of electrons = 0.6299 x 6.022 x 10^23 = 3.7933 x 10^23 electrons
hence 20 = 63.5/ 2 / 96500 x Ixt
Ix t = 20 x 96500 / 31.75 = 60787 C of electricity
96500 C passes 1 mole of electrons
hence 60787 will pass 1/96500 x 60787 moles of electrons = 0.6299 moles of electrons = 0.6299 x 6.022 x 10^23 = 3.7933 x 10^23 electrons
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