Physics, asked by lousistron170, 10 months ago

Emf of cell; ni|ni2+(1.0m)||au2+(1.0m)|auni|ni2+(1.0m)||au2+(1.0m)|au(where e0e0 for ni2+|nini2+|ni is 0.250.25v; e0e0 for au+2|auau+2|au is 1.501.50v) is:

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Answered by Sumedha27

1

The question is improper.........

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