Question

empirical formula of carbon having 52.94 carbon and 47.06 oxygen by mass

Answer 1

carbon % = 76.5%

Hydrogen % = 6.38%

Oxygen % =100-(76.5+6.38)

=100-82.88

=17. 12%

Now, Refers to the attachment for the

Empirical formula chart.

Empirical formula is C6H6O.

1. Empirical formula mass =(2x6+1x6+16=94g

. molecules mass =2 x vapor density

. Molecules mass = 2 x 47

. Molecules mass =94g.

. n =molecules mass /empirical formula mass =94/ 94

. molecules formula =1xC6H6O

= C6H6O