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A boatman goes 12 km against the current of thei stream in 6 hours and goes 2 km along the current in 50 minutes how long will it take for him to go 8km in still water?
[Note Select the accurate time in hours and minutes)
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InDOTECT EGETD
3 hrs 30 mins
3 hrs 38 mins​

Answer 1

Answer:

three hours and thirty eight minutes

Answer 2

Solution :-

we know that,

• Downstream Speed = (Speed of Boat in Still water + Speed of Water in The river).
• Upstream Speed = (Speed of Boat in Still water - Speed of Water in The river).

so, Let us assume that, the speed of boatman is still water is x km/h and speed of current is y km/h .

then,

→ (x - y) = 12/6 { S = D/T } .

→ x - y = 2 ---------- Eqn.(1)

and,

→ x + y = 2/(50/60) = 2 * (6/5) = 12/5 ---------- Eqn.(2)

adding Eqn.(1) and Eqn.(2),

→ x - y + x + y = 2 + (12/5)

→ 2x = (22/5)

→ x = (11/5) km/h .

putting value of x in Eqn.(1),

→ (11/5) - y = 2

→ y = (11/5) - 2

→ y = (1/5) km/h .

therefore,

→ Time taken to cover 8km in still water = D/S = 8/(11/5) = (40/11) hours = 3(7/11) = 3 + (7*60/11) = 3 + (420/11) ≈ 3 hours , 38 minutes (Ans.)

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