Math, asked by bhumi8tarodkar, 3 months ago

Encircle the number which are divisible by 2:428 517 138 189 2345 3456 4838​

Answers

Answered by JINSIPATEL
1

Answer:

428 ; 138 ; 3456 ; 4838

428 ; 138 ; 3456 ; 4838 This are the number divisible by 2.

Because at the once place there is even numbers so it is divisible by 2.

Answered by AadilPradhan
0

428, 138, 3456, 4838

Given:

428 517 138 189 2345 3456 4838​

To find:

Encircle the number which are divisible by 2

Solution:

For a number to be divisible by 2, it needs to have an even number like 2,4,6,8 or 0 as its last digit.

428 has its last digit has 8 which is an even number, so it is divisible by 2.

517 has its last digit has 7 which is not an even number, so it is not divisible by 2.

138 has its last digit has 8 which is an even number, so it is divisible by 2.

189 has its last digit has 9 which is not an even number, so it is not divisible by 2.

2345 has its last digit has 5 which is not an even number, so it is not divisible by 2.

3456 has its last digit has 6 which is an even number, so it is divisible by 2.

4838 has its last digit has 8 which is an even number, so it is divisible by 2.

Hence, the numbers divisible by 2 are 428, 138, 3456, 4838.

#SPJ2

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