Chemistry, asked by santhiya28, 6 months ago

Energy of an electron in the ground state of the hydrogen atom is -2.18×10-¹8 .Calculate the ionisation enthalpy the atomic hydrogen in terms of kj mol-¹​

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Answered by sujalnagar762
1

Answer:

ANSWER

Since IEHe+IELi2+=(ZHe+ZLi2+)2=49

∴IELi2+=49×IEHe+=9/4×19.6×10−18

                    =4.41×10−17J/atom

Energy  in stationary state =−IE=−4.41×10−17J/atom

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