Chemistry, asked by tejalkotak, 11 months ago

The wavelength associated with an electron moving with velocity 10^10 ms is
(1) 6.62 * 10-10 m
(2) 7.27 * 10-14 m
(3) 3.69 * 10-12 m
(4) 4.92 x 10-11 m​

Answers

Answered by Anonymous
11

lembda = h/mv

h = planks constant

h = 6.626x 10^-34 j/s

h =  {6.626} \times { {10}^{ - 34} }

mass \: of \: electron \\  =9.1 \times  {10 { }^{ - 31} } \: kg

Now put the all values in formula, lembda = h/mv

lembda =  \frac{6.626 \times  {10}^{34} }{9.1 \times  {10}^{ - 31 } \times  {10}^{10}  }

lembda = 7.27 \times  {10}^{ - 14} m

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