energy of an electron in the second Bohr orbit is -3.4ev calculate the energy of an electron in the third Bohr orbit.
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The energy of the electron in the second and third Bohr's orbitals of the hydrogen atom is -5.42×10-12erg and -2.42×10-12erg respectively ,Calculate the wavelength of the emitted radiation when the electron drop from the third to the second orbit.
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Yo
Energy of electron revolving in nth orbit is;
En = -13.6/n^2 eV
thus energy of electron revolving in (n =3)
E3 = -13.6/3^2 eV
E3. =-13.6/9 eV
E3. = -1.51 eV
this is the required answer dear
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