Physics, asked by shaheer5492, 1 year ago

Energy of photon whose frequency is 10¹² MHz, will be(a) 4.14×10³ keV(b) 4.14×10² eV(c) 4.14×10³ MeV(d) 4.14×10³ eV

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Answered by anitagorai

4

answer is d.

first calculate energy and then divide it by charge of one electron to get ans. in eV.

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