Energy of the lowest level of hydrogen atom is -13.6 eV. The energy of the photon emitted in the transition from n = 3 to n = 1 is
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Class 12
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>>Energy levels of H atom are...
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Energy levels of H atom are given by E
n
=−
n
2
13.6
eV, where n is principal quantum number. Calculate the wavelength of electromagnetic radiation emitted by hydrogen atom resulting from the transition: n=2 to n=1.
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E
n
=
n
2
−13.6
eV.
n=2 to n=1
λ=?
∴E
2
=
2
2
−13.6
=−3.4eV
and E
1
=
1
2
−13.6
=−13.6eV.
ΔE=E
2
−E
1
=−3.4−(−13.6)=10.2eV.
We know that Δ=
λ
hc
∴λ=
10.2×1.6×10
−19
6.6×10
−34
×3×10
8
=1.213×10
−7
=1213
A
o
.
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