Question

Energy of the radiation emitted during transition between the energy levels 'n1' and 'n2' of hydrogen atom, for which n2-n1 = 2 and n2/n1 = 2 is​

Answer 1

ANSWER

By Bohr's model, energy in nth orbit is given by

n

2

−13.6Z

2

where Z is the atomic number of the atom. Using the given formula, energies of different states are obtained as shown in the image. Now when transition is made from n=2 to n=1, a photon of 13.6-3.4=10.2 eV energy is released.

When this falls on helium atom:

When it falls on n=1 state, the minimum energy required to make a transition is 54.5-13.6=40.2 eV. Hence non transition is possible with this photon,

When it falls on n=2 state, a transition can directly be made from n=2 to n=4 as the energy required for this is 10.2 eV only. Or it can first make a transition to n=3 state and then n=4.

solution

Answer 2

Answer:

it's correct 12.75 ev so it's answer is option b it's from icon or ipl