Question

energy released by e during transition of 3rd balmer series of H atom is used to excite the e present in 4th shell of He+ ion. what is the excited state of He+ ion please give correct answer don't spam it​

Answer 1

Answer:

Hope it helps u

mark aa brainliest

Explanation:

Given λ

2

=30.4×10

−7

cm

λ

1

=108.5×10

−7

cm

Suppose excited state of He

+

is n

2

. The electron falls from n

1

to n

1

and then n

1

to 1 energy level to emit two successive photons.

∴

λ

2

1

=R

H

×Z

2

[

1

2

1

−

n

1

2

1

]

or

30.4×10

−7

1

=109678×4[

1

2

1

−

n

1

2

1

]

∴n

1

=2

Now for λ

1

:n

1

=2 and n

2

=n

∴

λ

1

1

=R

H

×Z

2

[

2

2

1

−

n

3

1

]

or

108.5×10

−7

1

=109678×4[

2

2

1

−

n

2

2

1

]

∴n=5

Thus, the excited state of He

+

is 5th orbit.

Hence, the correct option is B