Question

Energy stored in a capacitor is given by U = "/(CV) and potential V is defined as work done per unit charge, then find out the dimension of C.

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Answer 1

⚠⭐《ANSWER》

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↪Actually welcome to the concept of the CAPACITORS

↪Basically we know that , the charge is directly proportional to the voltage in case of the CAPACITORS, thus we get as

↪Q = C V

↪Thus we derive as , Capacitance is charge per unit Voltage .↪so we get as ,

↪C = Q/V

↪since, Q = I t and V = W/ Q

↪we get after substituing as ,

↪C = Q / ( W/Q) =》 Q^2 / W

↪thus , dimensions of Q are [ I T ] And W are [ M L^2 T^-2 ]

↪thus C has dimensions as 〽[C] = [ M^-1 L^-2 I^2 T^4 ]

Answer 2

Answer:

Explanation:we are using the formula of U to find its dimension & also use the formula V & then square it according to the question and simply use in the equation ✌️