Question

Energy stored in capacitor and dissipated during charging a
capacitor bear a ratio
[MP PMT 2010)
(a) 1:1
(b) 1:2
(c) 1:1/2
(d) 2:1​

Answer 1

Answer:

Explanation:

Here is answer. I hope it will help you.

Answer 2

Answer:

Energy stored in capacitor and dissipated during charging a capacitor bear a ratio 1:1

So, Option (a) is correct answer.

Explanation:

Energy stored in capacitor,

$U= \frac{1}{2} C {V}^{2}$

Where C is capacitance.

Work done by cell ,W = q x emf of cell

                                      = $CV \times V =C {V}^{2}$

Heat produced is given by

=  $C {V}^{2} - (\frac{1}{2} C {V}^{2} - 0) = \frac{1}{2} C {V}^{2}$

Now,

           $\frac{energy \: stored}{heat \: produced} = \frac{\frac{1}{2} C {V}^{2} }{\frac{1}{2} C {V}^{2} } = \frac{1}{1}$

∴ Energy stored in capacitor and dissipated during charging a capacitor bear a ratio 1:1.