Question

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Engine of a train exerts a force of 6000 N. If total mass of the train and the engine be 18000 kg, and initially the train was standing on the platform, what is the magnitude of velocity attained by the train 20 s after the start? Assume that there is no frictional force between railway track and the train and motion is in a horizontal direction.
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Answer 1

Explanation:

F=ma

6000n=18000(v-u/t)

=18000*v/20

= 900v

v= 6000/900

= 6.67 m /s

Answer 2

Answer:

6.67 m/s

Explanation:

F=6000N

M18000Kg

u=0

v=?

T=20sec

F=M*A

F/M=A

6000/18000=A

1/3

using first law of equation =v=u+at

v=0+1/3×20

6.67m/s

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