Question

English
64 mL of an unknown gas diffuses in same time as 128 mL of methane gas under identical conditions. The molar mass of unknown gas is
0 32 g mol-
O 48 g mol-1
O 96 g mol-1
O 64 g mol inverse​

Answer 1

Answer:

d anwer is correct 64g mol inverse

Answer 2

The molar mass of unknown gas is 64 mole

Therefore, option (d) is correct.

Explanation:

Given:

64 mL of an unknown gas diffuses in same time as 128 mL of methane gas under identical conditions.

To find out:

The molar mass if the unknown gas

Solution:

Given

Rate of diffusion of unknown gas = 64 mL

$\implies r_1=64$

Rate of diffusion of methane gas = 128 mL

$\implies r_2=128$

We know that molar mass of methane (CH₄) = 16

Thus,

$m_2=16$

We also know that

$\frac{r_1}{r_2}=\sqrt{\frac{m_2}{m_1}}$

$\implies \frac{64}{128}=\sqrt{\frac{16}{m_1}}$

$\implies \sqrt{\frac{16}{m_1}}=\frac{1}{2}$

$\implies \frac{16}{m_1}=\frac{1}{4}$

$\implies m_1=64$

Thus, the molar mass of unknown gas is 64

Hope this answer is helpful.

Know More:

Q: An unknown gas diffuses four times faster than oxygen . Calculate the molecular mass of the gas.

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