enjoy 50 points back to back
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Answered by
3
Given that, diameter(d) of cylinder is 1.4 m and length(h) is 8 m.
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)
= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)
= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20
Answered by
0
hey MATE!
HERE IS UR ANSWER!
EXTERNAL DIAMETER OF CYLINDER IS 1.4 M,radius =0.7m
LENGTH =8M
AREA OF CYLINDER=2*Pi*r (h+r)
2×22/7*0.7*(8+0.7)
44/7×0.7*8.7
41.36metre square.
cost =20×41.36
=827.20 rupees
HOPE IT HELPS
MARK BRAINLIEST PLZ♥♥♥
HERE IS UR ANSWER!
EXTERNAL DIAMETER OF CYLINDER IS 1.4 M,radius =0.7m
LENGTH =8M
AREA OF CYLINDER=2*Pi*r (h+r)
2×22/7*0.7*(8+0.7)
44/7×0.7*8.7
41.36metre square.
cost =20×41.36
=827.20 rupees
HOPE IT HELPS
MARK BRAINLIEST PLZ♥♥♥
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