Question

Enter an inequality that represents the description, and then solve. Twice a number (x) is more than 10.

Answer 1

Given that Twice a number is more than 10.

Let's assume the number is x.

So twice the number will be 2x

According to question, 2x is greater than 10

=> 2x > 10

=> x > 10/2

=> x > 5

Thus x can be any number greater than 5.

If x is a real number, we can write $x \in (5, \infty)$

Answer 2

Enter an inequality that represents the description, and then solve.

Twice a number (x) is more than 10.


$\huge \underline \mathfrak {Solution:-}$

Let the number be x.

Twice of number = 2x

It is given in the question that:-

Twice of number is more than 10.

So,

$2x > 10 \\ \\on \: dividing \: both \: sides \: by \: 2 \\ \\ \frac{2x}{2} > \frac{10}{2} \\ \\ x > 5$

The value of x is greater than 5.

It can be 6,7,8......

So, we may write it as

x € (5, infinity)