Chemistry, asked by sanjeevsony3476, 1 year ago

Enthalpy is an extensive property. In general, if enthalpy of an overall reaction A → B along one route is  \triangle _f H and  \triangle _f H_{1}, \triangle _f H_{2}, \triangle _f H_{3}... which represents enthalpies of intermediate reactions leading to product B. What will be the relation between  \triangle _f H for overall reaction and  \triangle _f H_{1}, \triangle _f H_{2}... etc. for intermediate reactions.

Answers

Answered by phillipinestest
5

“Enthalpy”:

It is defined as the sum of “internal energy” and product of “pressure and volume”.

H\quad =\quad U\quad +\quad PV

Relation between internal energy and enthalpy, \Delta H\quad =\quad \Delta U\quad +\quad \Delta PV

\Delta n\quad =\quad Number\quad of\quad gaseous\quad products\quad -\quad Number\quad of\quad gaseous\quad reactants

If\quad \Delta n\quad =\quad +ve,\quad \Delta H\quad >\quad \Delta U

If\quad \Delta n\quad =\quad -ve,\quad \Delta H\quad <\quad \Delta U

If\quad \Delta n\quad =\quad 0,\quad \Delta H\quad =\quad \Delta U

From the given data,

A\rightarrow B

{ \Delta }_{ r }H, { \Delta }_{ r }{ H }_{ 2 },{ \Delta }_{ r }{ H }_{ 3 } are different enthalpies.

According to the Hess law,

{ \Delta }_{ r }H\quad =\quad { \Delta }_{ r }H\quad +\quad { \Delta }_{ r }{ H }_{ 2 }\quad +{ \Delta }_{ r }{ H }_{ 3 }

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