Chemistry, asked by anwaarshahanw6371, 1 year ago

Enthalpy of atomization for reaction ch4(g) - c(g) + 4h(g) is 1665 KJmol. what is bond energy of c-h bond?

Answers

Answered by Anonymous
35
HEY USER...

METHANE HAS 4 C-H BONDS

SO BOND ENERGY IS 1665/4 = 416.25KJ/MOLE

THANK YOU

HOPE IT HELPS
Answered by zumba12
5

The bond energy of the C-H bond is 416.2kJ mol

  • The given reaction is as follows:

CH_4\rightarrow C+4H

  • The enthalpy of atomization refers to the energy required to separate all the atoms attached in a compound and for the given reaction it is 1665 KJ mol.
  • As in this case, carbon is attached with 4 hydrogen atom with a single bond, the bond energy of the C-H bond is calculated as follows:

Bond energy = \frac{Enthalpy of atomization}{Number of bonds}

Bond energy = \frac{1665}{4}

Bond energy = 416.2kJ mol

  • The bond energy of C-H bond is calculated as 416.2kJ mol.

Learn more about such concept

What is bond theory define factors attesting bond energy?

https://brainly.in/question/4675353

Calculate bond energy of HCl if bond enthalpy of H2 and Cl2 are 430 and 242 KJ/Mol respectively and heat of formation of HCl is - 91 KJ/Mol.

https://brainly.in/question/6247164

Similar questions