Question

Enthalpy of neutralisation of hcl by naoh is -55.84 and by nh4oh is -51.34 the enthalpy of ionisation of nh4oh is

Answer 1

neutralization reaction is a type of reaction of acid reacts with base to form salt and water

Answer 2

Answer: Enthalpy of ionization of $NH_4OH$ is 4.5 kJ

Explanation:

We are given:

Enthalpy of neutralization of NaOH by HCl = -55.84 kJ

Enthalpy of neutralization of $NH_4OH$ by HCl = -51.34 kJ

To calculate the enthalpy of ionization of $NH_4OH$, we use the equation:

$\text{Enthalpy of ionization of }NH_4OH=\text{Enthalpy of neutralization of }NH_4OH-\text{Enthalpy of neutralization of NaOH}$

Putting values in above equation, we get:

$\text{Enthalpy of ionization of }NH_4OH=[-51.34-(-55.84)]kJ=4.5kJ$

Hence, the enthalpy of ionization of $NH_4OH$ is 4.5 kJ