Question

enthalpy of neutralization of 0.2mol H+ with 0.1 mol OH- isA) 13.7kcalB)2.74kcalC)27.4kcalD)1.37kcal​

Answer 1

Answer: A) 13.7kcal

Explanation: Enthalpy of neutralization is defined  as the amount of heat released when 1 gram equivalent of acid is neutralized by 1 gram equivalent of base. It is calculted to be 56.4 kJ/mol or 13.7 kcal/mol for strong acid and strong base.

$H^++OH^-\rightarrow H_2O$

According to stochiometry, 1 mole of $H^+$ or 1 gram equivalent of $H^+$ is neutralized by 1 mole of $OH^-$ or 1 gram equivalent of $OH^-$.

Thus enthalpy of neutralization is found to be 13.7 kcal.