Question

ents.
The following table shows the weight of 15 studeni
Weight (in kg) 47 50 53 | 56 60
No. of students 4 3 2 2 4
Find the mean, median and mode for the above data.
17.7​

Answer 1

Answer:

Mean = 53.067

Median = 53

Mode = 47 and 60 - This data is Bimodal

Step-by-step explanation:

We are given the following data below;

   Weight (in Kg) - X             No. of students (f)       cf                 X*f            

             47                                         4                         4                 188

             50                                         3                         7                150

             53                                         2                         9                106

             56                                         2                         11                112

             60                                         4                         15               240

• Mean = $\frac{\sum Xf}{\sum f}$ = $\frac{796}{15}$ = 53.067

• Median is given by;

             First we calculate $\frac{N}{2}$ , where N = ∑f  ⇒ $\frac{15}{2}$ = 7.5

          Here, value of cf just greater than or equal to 7.5 is 9.

          Therefore, Median = 53 because the weight corresponding to cf of 9

            is 53.

• Mode is the number which appears maximum times in our data.

        Here two weights 47 and 60 have the same frequency so we conclude

        this data is Bimodal i.e. having two modes.