Question

epaper in the form of a rectangle pqrs in which PQ equal to 20 cm and QR equal to 14 cm a semicircle person with QR as diameter is cut off find the area of the remaining part

Answer 1

area of remaining part =area of rectangle-area of semi circle
=14*20cm-1/2πr^2
=280-1/2*22/7*7*7
=280-77
=203cm²

I hope it helps

Answer 2

Length of Rectangle ( PQ) = 20 cm

Breadth of Rectangle (QR) = 14 cm

Diameter of Semi- Circle = 14 cm

Radius Of Semi-Circle = 7 cm

Area of Remaining Portion = Area Of Rectangle – Area Of Semi-Circle

Area Of Rectangle = Length × Breadth

Area Of Rectangle = 20×14

Area Of Rectangle = 280 cm²

Area Of Semi-Circle = πr²/2

Area Of Semi-Circle = π7²/2

Area Of Semi-Circle = 76.96 cm²

Area Of Remaining Portion = Area Of Rectangle – Area of Semi-Circle

Area Of Remaining Portion = 280 – 76.96

Area Of Remaining Portion = 203.07 cm²