Equal amounts of sodium hydrogencarbonate are taken in two test tubes A and B. Acetic acid is added to test-tube A whereas an equal volume of hydrochloric acid is added to test-tube B. In which test-tube, effervescence will occur more vigorously and why?
Answers
Answer:
Explanation:
Sodium hydrogencarbonate on reaction with acetic acid releases carbon dioxide gas. NaHCO3 + CH3COOH → CH3COONa + H2O + CO2 Test for carbon dioxide: The presence of carbon dioxide can be tested by bringing a burning splinter near the mouth of the cylinder containing carbon dioxide – it gets extinguished. If carbon dioxide is passed through limewater, it turns milky white. Ca(OH)2 + CO2 → CaCO3 + H2O
Answer:
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Fizzing will occur more vigorously in test tube A. Hydrochloric acid (HCl) is a strong acid whereas acetic acid (CH3COOH) is a weak acid. Being strong acid, the hydrochloric acid solution contains a much greater amount of hydrogen ions in it due to which the fizzing will occur more vigorously in test tube A (containing hydrochloric acid). The fizzing is due to the evolution of hydrogen gas which is formed by the action of acid on the magnesium metal of magnesium ribbon.