Equal heat is given to two objects A and B of masses 1 g. Temperature
of A increases by 3°C and B by 5°C. Which object has more specific
heat and by what factor?
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Answer:
Given that mass of A and B is equal and =1g=m
A
=m
B
Given change in temperature of A=ΔT
A
=3
0
C
change in tem. of B=ΔT
B
=5
0
C
Given that Equal amount of heat is applied to both
for A:Q=m
A
S
A
ΔT
A
=3S
A
............(i)
for B:Q=m
B
S
B
ΔT
B
=5S
B
............(ii)
Where S
A
and S
B
are specific heat of A and B
From eq (i),(ii)
3S
A
=5S
B
⇒
S
A
=
3
5
S
B
Hence specific heat of A is greater than that of B by a factor of 5/3
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