Equal masses of H2 and N2 are mixed in the container at 25°C.fraction of total pressure
exerted by H2 is
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Given:
- The mass of H₂ taken is equal to the mass of the N₂ taken = W g
- Molar mass of H₂ = 2 g/mol
- Molar mass of N₂ = 28 g/mol
To find:
The fraction of the total pressure exerted by H₂
Solution:
- According to Dalton's law of partial pressure of gases, the fraction of total pressure exerted by a gas in a mixture of gases is equal to the mole fraction of the gas.
- Moles of H₂ (n1) = W/2
- Moles of N₂ (n2) = W/28
- Total number of moles (n) = n1 + n2 = (W/2) + (W/28) = 15W/28.
- Mole fraction of H₂ = n1/n = (W/2)/(15W/28) = 14/15
Answer:
The volume of water (V) that needs to be added to the mixture of the two solution such that the resulting molarity is 3M = 14/15.
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