Question

equal masses of H2 O2 a Methane have been taken in a container of volume v at temperature 27 degree celsius in identical conditions the ratio of the volume of the gases H2O to Methane would be

Answer 1

Let the mass of each gas be w.

So no. Of moles of H2= w/2
No of moles of O2= w/32
No.of moles of CH4 = w/16

So volume of H2 = w/2 * 22.4L
Volume of O2 = w/32 * 22.4L
Volume of CH4 = w/16 * 22.4L

So the ratio will be 1/2 : 1/32 : 1/16 = 16: 1 : 2

Answer 2

Answer:

1 Ratio 2

Explanation:

Mole - The General Assembly for Weights and Measures (CGPM) proposed to revise the International System of Units (SI) so that all its base units are defined by an "explicit constant" formula. (1) In particular he wrote that the draft definitions of the "new SI" of two units, the mole and the kilogram, have been scrutinized by chemists. For example, the ACS Committee on Nomenclature, Terminology, and Symbols has overseen proposals on these entities for several years, sponsored symposia on the subject at national conferences, and published commentaries in Chemical and Engineering News. It is intended to teach moles in introductory chemistry classes, focusing on the current definition of moles and the definitions contained in the new SI 2013 draft brochure. In order to harmonize the official definition with current educational practice, several current textbooks have been examined on mole teachings. To put the possible impact of the proposed change in historical perspective, we compare it with the impact of the previous major change in SI for chemists, namely the inclusion of moles as SI base units in 1971.

Current-The Mol is the amount of matter in a system containing as many base units as there are atoms in 0.012 kilograms of carbon-12. Its symbol is "mol".

Solving way-

No. Of moles of$H2$=$w/2$

No of moles of $O2$=$w/32$

No .of moles of $CH4$ =$w/16$

So volume of $H2$= $w/2 * 22.4L$

Volume of$O2$ =$w/32 * 22.4L$

Volume of $CH4$ = $w/16 * 22.4L$

Therefore the ratio will be $1/2 : 1/32 : 1/16 = 16: 1 : 2$

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