Equal masses of H2, O2 and methane have been taken in a container of volume V at temperature
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At least complete the question. The question is as follows:
Equal masses of H2 O2 a Methane have been taken in a container of volume v at temperature 27 degree celsius in identical conditions the ratio of the volume of the gases H2O to Methane would be????
Answer:
Let the mass of each gas be w.
So no. Of moles of H2= w/2
No of moles of O2= w/32
No.of moles of CH4 = w/16
So volume of H2 = w/2 * 22.4L
Volume of O2 = w/32 * 22.4L
Volume of CH4 = w/16 * 22.4L
So the ratio will be 1/2 : 1/32 : 1/16 = 16: 1 : 2
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