Question

Equal masses of methane and oxygen are mixed in an empty container at 25 degree celsius

Answer 1

Answer:

Let weight of Oxy and methane be ‘x’ gram.

And let volume be ‘v’ liter

Now, calculate the mole of each:-

i.e Oxy = x/32 and methane =x/16

Partial pressure of Oxy =mole fraction of oxy ×P (total).

mole fraction= (x/32)/(x/32)+x/16

Now, mole fraction of O2 =1/3

Partial Pressure of oxygen=1/3P.

Fraction of total pressure is 1/3P(total).

Explanation: