Question

Equation of a tangent to the parabola (y + 1)^2 = 4x, which passes through the point (0, 3), is

Answer 1

The standard form is (x - h)2 = 4p (y - k), where the focus is (h, k + p) and the directrix is y = k - p. If the parabola is rotated so that its vertex is (h,k) and its axis of symmetry is parallel to the x-axis, it has an equation of (y - k)2 = 4p (x - h), where the focus is (h + p, k) and the directrix is x = h - p.

Answer 2

Step-by-step explanation:

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