Equal torques act on the discs A and B of the previous problem, initially both being at rest. At a later instant, the linear speeds of a point on the rim of A and another point on the rim of B are vA and vB respectively. We have
(a) vA > vB
(b) vA = vB
(c) vA < vB
(d) the relation depends on the actual magnitude of the torques.
Answers
Answered by
6
Answer ⇒ Option (a) . vA > vB
Explanation ⇒
Assuming that the T be the torque and A and A' be the angular accelerations.
∴ A = T/IA & A' = T/IB.
Clearly A >A'.
Commonly, the ratio of the moment of Inertia is highest. Thus, at a later instant, the angular velocity of the first disc will be much greater than the second.
Hence option (a). is correct.
Hope it helps.
Answered by
2
Answer:
Answer ⇒ Option (a)
. vA > vB
Explanation ⇒
Assuming that the T be the torque and A and A' be the angular accelerations.
∴ A = T/IA & A' = T/IB.
Clearly A >A'.
Commonly, the ratio of the moment of Inertia is highest. Thus, at a later instant, the angular velocity of the first disc will be much greater than the second.
Hence option (a). is correct.
Hope it helps.
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