equal volume of each 10% HCL and 10% analysis next comment on the nature of resulting solution
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Given volume of acid (HCl) is 50 ml and concentration is 0.4 N
Volume of base (NaoH) is 50ml and concentration is 0.2 N .
Actually it is simple reaction in which salt is formed then some acid is remains find pH of that acid .
Base is 0.2 * 50Nml = 10Nml
Acid is 0.4*50Nml = 20Nml.
So remaining acid is 20–10 = 10Nml in 100ml of solution. So concentration of acid is 10/100N = 0.1N
So pH is -log[H+]
pH = -log(0.1)
= 1.
Therefore pH of solution is 1
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