Question

Equal volumes of 0.1 M NaNO3 and 0.2 M NaCl solutions are mixed. The concentration of nitrate ions in the resultant mixture will be 
 1) 0.1 M 2) 0.2 M 3) 0.05 M 4) 0.15 M 

Answer 1

NaNO3 ---------------------->Na+   +   NO3-
molarity of NaNO3 = molarity of NO3-
apply , M1V1 = M2V2 
M1 = 0.1 ,V1 = V ,M2 = ?  ,V2 = 2V
M2 = 0.1/2
      = 0.05M
hence option (3) is correct