If 20 ml of 1M HCl solution is exactly neutralised by 10 ml of Ca (OH)2 solution, the strength of Ca(OH)2 in grams per litre of the solution is
1) 37 2) 74 3)111 4)148
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normality of HCl = 1*molarity of HCl
= 1N
apply N1V1 = N2V2
1*20 = N2*10
N2 = 2
molarity of Ca(OH)2 = N2/2
= 2/2 = 1M
molarity = no.of moles/volume of solution in L
= weight/(molecular weight*volume of solution in L)
1 = weight/(74*volume of solution in L)
74 = strength (in gram/L)
hence (2) option is correct
= 1N
apply N1V1 = N2V2
1*20 = N2*10
N2 = 2
molarity of Ca(OH)2 = N2/2
= 2/2 = 1M
molarity = no.of moles/volume of solution in L
= weight/(molecular weight*volume of solution in L)
1 = weight/(74*volume of solution in L)
74 = strength (in gram/L)
hence (2) option is correct
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