Equal volumes of 1 M each of KMnO4 and K2Cr2O7 are used to oxidize Fe(II) solution in acidic medium. The amount of Fe oxidized will be
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Explanation:
The 'n' factor of KMnO4 is 5 while that of K2Cr2O7 is 6. So for the same number of moles, K2Cr2O7 will have greater equivalents than KMnO4.
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